Semiconductor Electronics question for JEE Main (JEE Main 2019 (12 Apr, Shift 1)), with solution

Answer: (D) $\begin{array}{ccc}A & B & Y\\ 0 & 0 & 1\\ 0 & 1 & 1\\ 1 & 0 & 0\\ 1 & 1 & 0\end{array}$

$$Y = \overline{A\cdot(A + B)} = \overline{A + AB} = \overline{A}$$

So $Y = 1$ when $A = 0$ and $Y = 0$ when $A = 1$, whatever $B$ is.

Solution by Sreeraj P, M.Sc Physics