Q 12-14-001NEETNEET 2026Top questionEasy
An ideal Zener diode with breakdown voltage of $-3$ V is reverse biased with a negative input voltage $V_i = -5$ V. The magnitude of voltage difference between points $B$ and $A$ is :
Answer: (B) $2$ V
The reverse-biased Zener is in breakdown, since $5\ \text{V} > 3\ \text{V}$. An ideal Zener then holds a constant $3$ V across itself (between C and B).
The rest of the supply voltage appears across the resistor R, which lies between B and A:
$$|V_B - V_A| = 5 - 3 = 2\ \text{V}$$
Solution by Sreeraj P, M.Sc Physics