Q 12-14-007NEETNEET 2024Top questionEasy
A logic circuit provides the output $Y$ as per the following truth table :
$$\begin{array}{|c|c|c|}\hline A & B & Y \\ \hline 0 & 0 & 1 \\ 0 & 1 & 0 \\ 1 & 0 & 1 \\ 1 & 1 & 0 \\ \hline\end{array}$$
The expression for the output $Y$ is :
Answer: (A) $\bar{B}$
Look at the table: $Y = 1$ exactly when $B = 0$, and $Y = 0$ exactly when $B = 1$, whatever the value of $A$.
So $Y = \bar{B}$.
(Check the other options: $A \cdot B + \bar{A}$ gives $1$ for $A = 0, B = 1$, and $A\cdot\bar{B} + \bar{A}$ also gives $1$ for $A = 0, B = 1$; both disagree with the table.)
Solution by Sreeraj P, M.Sc Physics