Q 12-14-012NEETNEET 2021Top questionEasy
The electron concentration in an n-type semiconductor is the same as hole concentration in a p-type semiconductor. An external field (electric) is applied across each of them. Compare the currents in them.
Answer: (D) current in n-type > current in p-type.
The current is $I = neAv_d = neA\mu E$. The carrier concentrations are equal, but electrons have a higher mobility than holes ($\mu_e > \mu_h$).
So the current in the n-type semiconductor is greater.
Solution by Sreeraj P, M.Sc Physics