Q 12-14-017NEETJEE MainEasy
A silicon diode (cut-in voltage $0.7$ V) is connected in forward bias in series with a $1\ \text{k}\Omega$ resistor across a $5$ V battery. The current in the circuit is
Answer: (A) $4.3$ mA
The diode takes $0.7$ V, so the resistor has $5 - 0.7 = 4.3$ V across it.
$I = \dfrac{4.3}{1000} = 4.3$ mA.
Solution by Sreeraj P, M.Sc Physics