A silicon diode (cut-in voltage 0.7 V) is connected in forward bias in series with a 1 kΩ resistor across a 5 V battery. The current in the circuit is

(A) 4.3 mA. The diode takes 0.7 V, so the resistor has 5 - 0.7 = 4.3 V across it. I = (4.3)/(1000) = 4.3 mA.

Semiconductor Electronics question for NEET / JEE Main, with solution

Q 12-14-017NEETJEE MainEasy

A silicon diode (cut-in voltage $0.7$ V) is connected in forward bias in series with a $1\ \text{k}\Omega$ resistor across a $5$ V battery. The current in the circuit is

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Semiconductor Electronics question for NEET / JEE Main, with solution

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