Q 12-14-193JEE MainJEE Main 2019 (12 Apr, Shift 2)Easy
In a CE transistor amplifier, the audio signal voltage across the collector resistance of $2$ kΩ is $2$ V. If the base resistance is $1$ kΩ and the current amplification of the transistor is $100$, then the input signal voltage is
Answer: (A) $10$ mV
$I_C = \dfrac{2}{2000} = 1$ mA, so $I_B = \dfrac{1\ \text{mA}}{100} = 10\ \mu$A.
$$V_{\text{in}} = I_BR_B = 10\times10^{-6}\times1000 = 10\ \text{mV}$$
Solution by Sreeraj P, M.Sc Physics