Q 12-14-125JEE MainJEE Main 2021 (27 Jul, Shift 1)Easy
A transistor is connected in common emitter circuit configuration, the collector supply voltage is $10$ V and the voltage drop across a resistor of $1000\ \Omega$ in the collector circuit is $0.6$ V. If the current gain factor $(\beta)$ is $24$, then the base current is ______ $\mu$A. (Round off to the nearest integer)
Numerical value type. Enter your answer.
Answer: 25
$I_C = \dfrac{0.6}{1000} = 0.6$ mA.
$$I_B = \frac{I_C}{\beta} = \frac{0.6\times10^{-3}}{24} = 25\times10^{-6}\ \text{A} = 25\ \mu\text{A}$$
Solution by Sreeraj P, M.Sc Physics