Q 12-14-126JEE MainJEE Main 2021 (27 Jul, Shift 2)Easy
Find the truth table for the function $Y$ of $A$ and $B$ represented in the following figure.
Answer: (B) $\begin{array}{|c|c|c|}\hline A & B & Y \\ \hline 0 & 0 & 1 \\ 0 & 1 & 0 \\ 1 & 0 & 1 \\ 1 & 1 & 1 \\ \hline\end{array}$
$Y = A\cdot B + \overline{B}$
$A=0,B=0$: $0 + 1 = 1$
$A=0,B=1$: $0 + 0 = 0$
$A=1,B=0$: $0 + 1 = 1$
$A=1,B=1$: $1 + 0 = 1$
So $Y = 1, 0, 1, 1$, which is table (2).
Solution by Sreeraj P, M.Sc Physics