Q 12-13-028JEE MainJEE Main 2026 (8 Apr, Shift 2)Medium
Two radioactive substances A and B of mass numbers $200$ and $212$ respectively, shows spontaneous $\alpha$-decay with same $Q$ value of $1$ MeV. The ratio of energies of $\alpha$-rays produced by A and B is ______.
Answer: (C) $\dfrac{2597}{2600}$
Concept. $K_\alpha=Q\dfrac{A-4}{A}$ with the same $Q$.
Step 1. Ratio. $\dfrac{196/200}{208/212}=\dfrac{196\times212}{200\times208}=\dfrac{2597}{2600}$.
Answer. Option C.
Solution by Sreeraj P, M.Sc Physics


