Q 12-13-034JEE MainJEE Main 2026 (28 Jan, Shift 2)Easy
A nucleus has mass number $\alpha$ and radius $R_\alpha$. Another nucleus has mass number $\beta$ and radius $R_\beta$.
If $\beta = 8\alpha$ then $R_\alpha/R_\beta$ is :
Answer: (D) 0.5
Nuclear radius $R = R_0A^{1/3}$, so
$$\frac{R_\alpha}{R_\beta} = \left(\frac{\alpha}{\beta}\right)^{1/3} = \left(\frac18\right)^{1/3} = \frac12 = 0.5$$
Solution by Sreeraj P, M.Sc Physics