Q 12-13-030JEE MainJEE Main 2026 (6 Apr, Shift 2)Medium
The energy released if hydrogen atoms are combined to form $^4_2\text{He}$ is ______ MeV. (Take binding energies per nucleon of $^2_1\text{H}$ and $^4_2\text{He}$ as $1.1$ MeV and $7.2$ MeV, respectively)
Answer: (B) $24.4$
Two deuterium nuclei fuse: $2\,^2_1\text{H} \to ^4_2\text{He}$.
Energy released = BE of products − BE of reactants $= 4 \times 7.2 - 2 \times (2 \times 1.1) = 28.8 - 4.4 = 24.4$ MeV.
Solution by Sreeraj P, M.Sc Physics