Q 11-03-104JEE MainJEE Main 2023 (1 Feb, Shift 1)Easy
A child stands on the edge of the cliff $10$ m above the ground and throws a stone horizontally with an initial speed of $5\ \text{m s}^{-1}$. Neglecting the air resistance, the speed with which the stone hits the ground will be ______ $\text{m s}^{-1}$ (given $g=10\ \text{m s}^{-2}$).
Answer: (B) 15
$v_y^2=2gh=200$, so $v=\sqrt{25+200}=15\ \text{m s}^{-1}$.
Solution by Sreeraj P, M.Sc Physics