Q 11-03-103JEE MainJEE Main 2023 (10 Apr, Shift 1)Easy
The range of the projectile projected at an angle of $15^\circ$ with horizontal is $50$ m. If the projectile is projected with same velocity at an angle of $45^\circ$ with horizontal, then its range will be
Answer: (A) $100\ \text{m}$
$\dfrac{u^2\sin30^\circ}{g}=50\Rightarrow\dfrac{u^2}{g}=100$. At $45^\circ$ the range is $\dfrac{u^2}{g}=100$ m.
Solution by Sreeraj P, M.Sc Physics