Match List-I with List-II:
$$\begin{array}{|l|l|l|l|}\hline & \text{List-I} & & \text{List-II} \\ \hline \text{A.} & \text{A force that restores an elastic body of unit area to its original state} & \text{I.} & \text{Bulk modulus} \\ \hline \text{B.} & \text{Two equal and opposite forces parallel to opposite faces} & \text{II.} & \text{Young's modulus} \\ \hline \text{C.} & \text{Forces perpendicular everywhere to the surface per unit area, same everywhere} & \text{III.} & \text{Stress} \\ \hline \text{D.} & \text{Two equal and opposite forces perpendicular to opposite faces} & \text{IV.} & \text{Shear modulus} \\ \hline \end{array}$$
Choose the correct answer from the options given below:
Answer: (B) (A)-(III), (B)-(IV), (C)-(I), (D)-(II)
- Restoring force per unit area → stress (III).
- Tangential forces on opposite faces change shape → shear modulus (IV).
- Uniform normal pressure on all of the surface changes volume → bulk modulus (I).
- Normal forces on opposite faces change length → Young's modulus (II).
Solution by Sreeraj P, M.Sc Physics