Q 11-08-043JEE MainJEE Main 2024 (9 Apr, Shift 1)Easy
Two persons pull a wire towards themselves. Each person exerts a force of $200\ \text{N}$ on the wire. Young's modulus of the material of the wire is $1\times10^{11}\ \text{N m}^{-2}$. Original length of the wire is $2\ \text{m}$ and the area of cross section is $2\ \text{cm}^2$. The wire will extend in length by ______ $\mu\text{m}$.
Numerical value type. Enter your answer.
Answer: 20
The tension in the wire is $200\ \text{N}$ (not $400\ \text{N}$):
$$\Delta l = \frac{FL}{AY} = \frac{200\times2}{2\times10^{-4}\times10^{11}} = 2\times10^{-5}\ \text{m} = 20\ \mu\text{m}$$
Solution by Sreeraj P, M.Sc Physics