Q 11-07-119JEE MainJEE Main 2022 (25 Jun, Shift 1)Easy
The height of any point $P$ above the surface of earth is equal to diameter of earth. The value of acceleration due to gravity at point $P$ will be: (Given $g$ = acceleration due to gravity at the surface of earth)
Answer: (D) $\dfrac g9$
$h = 2R$, so the distance from the centre is $3R$:
$$g' = g\left(\frac{R}{3R}\right)^2 = \frac g9$$
Solution by Sreeraj P, M.Sc Physics