Q 11-07-125JEE MainJEE Main 2022 (25 Jul, Shift 2)Easy
An object is taken to a height above the surface of earth at a distance $\dfrac54R$ from the centre of the earth, where the radius of earth $R = 6400\ \text{km}$. The percentage decrease in the weight of the object will be
Answer: (A) $36\%$
$$\frac{g'}{g} = \left(\frac{R}{5R/4}\right)^2 = \frac{16}{25} = 0.64$$
Decrease $= 36\%$.
Solution by Sreeraj P, M.Sc Physics