Q 11-07-126JEE MainJEE Main 2022 (26 Jul, Shift 1)Easy
The percentage decrease in the weight of a rocket, when taken to a height of $32\ \text{km}$ above the surface of earth, will be (Radius of earth $= 6400\ \text{km}$)
Answer: (A) $1\%$
For $h\ll R$: $\dfrac{\Delta g}{g} = \dfrac{2h}{R} = \dfrac{64}{6400} = 1\%$.
Solution by Sreeraj P, M.Sc Physics