Q 12-02-006NEETNEET 2024Top questionMedium
In the following circuit, the equivalent capacitance between terminal $A$ and terminal $B$ is :
Answer: (C) $2\ \mu$F
The four outer capacitors form a Wheatstone bridge with the middle $2\ \mu$F capacitor as the bridge. All four arms are equal ($2\ \mu$F each), so the bridge is balanced: the two middle junctions are at the same potential and the middle capacitor has no charge.
Each outer branch is two $2\ \mu$F capacitors in series: $1\ \mu$F.
Two such branches in parallel:
$$C_{AB} = 1 + 1 = 2\ \mu\text{F}$$
Solution by Sreeraj P, M.Sc Physics