Q 12-02-010NEETNEET 2023Top questionEasy
The equivalent capacitance of the system shown in the following circuit is :
Answer: (A) $2\ \mu$F
The two $3\ \mu$F capacitors on the right are in parallel: $3 + 3 = 6\ \mu$F.
This is in series with the $3\ \mu$F capacitor:
$$C = \frac{3 \times 6}{3 + 6} = 2\ \mu\text{F}$$
Solution by Sreeraj P, M.Sc Physics