Q 12-02-011NEETNEET 2023Top questionMedium
An electric dipole is placed as shown in the figure. The electric potential (in $10^2$ V) at point P due to the dipole is ($\epsilon_0$ = permittivity of free space and $\dfrac{1}{4\pi\epsilon_0} = K$):
Answer: (A) $\left(\dfrac{3}{8}\right)qK$
Concept. P is close to the dipole, so add the two point-charge potentials.
Step 1. Distances. $0.02$ m from $+q$, $0.08$ m from $-q$.
Step 2. Potential. $Kq(50 - 12.5) = 37.5Kq = \dfrac38 \times 10^2Kq$.
Answer. $\left(\dfrac38\right)qK$ (Option A).
Solution by Sreeraj P, M.Sc Physics