Q 12-02-008NEETNEET 2024Top questionEasy
A thin spherical shell is charged by some source. The potential difference between the two points $C$ and $P$ (in V) shown in the figure is:
(Take $\dfrac{1}{4\pi\epsilon_0} = 9 \times 10^9$ SI units)
Answer: (B) zero
Inside a charged conducting (thin) shell the electric field is zero, so the potential is the same everywhere inside and on the shell:
$$V = \frac{1}{4\pi\epsilon_0}\frac{q}{R}$$
$C$ is the centre and $P$ is on the shell, so $V_C = V_P$ and the potential difference is zero.
Solution by Sreeraj P, M.Sc Physics