Q 12-06-072JEE MainJEE Main 2023 (13 Apr, Shift 2)Medium
An insulated copper wire of $100$ turns is wrapped around a wooden cylindrical core of the cross-sectional area $24\ \text{cm}^2$. The two ends of the wire are connected to a resistor. The total resistance in the circuit is $12\ \Omega$. If an externally applied uniform magnetic field in the core along its axis changes from $1.5\ \text{T}$ in one direction to $1.5\ \text{T}$ in the opposite direction, the charge flowing through a point in the circuit during the change of magnetic field will be ______ mC.
Numerical value type. Enter your answer.
Answer: 60
$$q=\frac{N\Delta\phi}{R}=\frac{100\times(1.5+1.5)\times24\times10^{-4}}{12}=0.06\ \text{C}=60\ \text{mC}$$
Solution by Sreeraj P, M.Sc Physics