Q 12-06-071JEE MainJEE Main 2023 (25 Jan, Shift 2)Easy
A wire of length $1\ \text{m}$ moving with velocity $8\ \text{m s}^{-1}$ at right angles to a magnetic field of $2\ \text{T}$. The magnitude of induced emf between the ends of wire will be ______.
Answer: (D) $16\ \text{V}$
$\varepsilon=Blv=2\times1\times8=16\ \text{V}$.
Solution by Sreeraj P, M.Sc Physics