Q 12-03-075JEE MainJEE Main 2024 (1 Feb, Shift 1)Easy
The current in a conductor is expressed as $I = 3t^2 + 4t^3$, where $I$ is in ampere and $t$ is in second. The amount of electric charge that flows through a section of the conductor from $t = 1\ \text{s}$ to $t = 2\ \text{s}$ is ______ C.
Numerical value type. Enter your answer.
Answer: 22
$$q = \int_1^2(3t^2 + 4t^3)\,dt = \Big[t^3 + t^4\Big]_1^2 = (8 + 16) - (1 + 1) = 22\ \text{C}$$
Solution by Sreeraj P, M.Sc Physics