Q 12-03-045JEE MainMedium
Using Kirchhoff's laws, find the current, in amperes, through a $2\ \Omega$ resistor connected between the positive terminals of two cells whose negative terminals are joined, with emfs $10$ V and $4$ V and negligible internal resistance.
Numerical value type. Enter your answer.
Answer: 3
The loop has net emf $10 - 4 = 6$ V (the cells oppose each other around the loop) and resistance $2\ \Omega$: $I = 3$ A.
Solution by Sreeraj P, M.Sc Physics