Q 12-03-029NEETJEE MainMedium
A $12\ \Omega$ wire is bent into a circle. The resistance between two points that subtend $90°$ at the centre is
Answer: (B) $2.25\ \Omega$
The arcs are $3\ \Omega$ and $9\ \Omega$ in parallel: $\dfrac{3 \times 9}{12} = 2.25\ \Omega$.
Solution by Sreeraj P, M.Sc Physics