Q 12-03-028NEETJEE MainMedium
A $12\ \Omega$ wire is bent into a circle. The resistance between two points at the ends of a diameter is
Answer: (A) $3\ \Omega$
The two semicircles ($6\ \Omega$ each) are in parallel: $\dfrac{6 \times 6}{12} = 3\ \Omega$.
Solution by Sreeraj P, M.Sc Physics