Q 12-03-034NEETJEE MainMedium
Two cells of emf $2$ V and $4$ V, with internal resistances $1\ \Omega$ and $2\ \Omega$, are connected in parallel (like terminals together). The emf of the combination is
Answer: (C) $\dfrac{8}{3}$ V
$E_{eq} = \dfrac{E_1/r_1 + E_2/r_2}{1/r_1 + 1/r_2} = \dfrac{2 + 2}{1 + 0.5} = \dfrac{8}{3}$ V.
Solution by Sreeraj P, M.Sc Physics