A cell gives 0.5 A through a 4 Ω resistor and 0.9 A through a 2 Ω resistor. Its internal resistance is

(D) 0.5 Ω. E = 0.5(4 + r) = 0.9(2 + r) 2 + 0.5r = 1.8 + 0.9r r = 0.5 Ω (and E = 2.25 V).

Current Electricity question for NEET / JEE Main, with solution

Q 12-03-031NEETJEE MainMedium

A cell gives $0.5$ A through a $4\ \Omega$ resistor and $0.9$ A through a $2\ \Omega$ resistor. Its internal resistance is