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Atoms question for JEE Main (JEE Main 2022 (27 Jun, Shift 2)), with solution

Q 12-12-091JEE MainJEE Main 2022 (27 Jun, Shift 2)Easy

Given below are two statements

**Statement I:** In hydrogen atom, the frequency of radiation emitted when an electron jumps from lower energy orbit $(E_1)$ to higher energy orbit $(E_2)$, is given as $hf = E_1 - E_2$

**Statement II:** The jumping of electron from higher energy orbit $(E_2)$ to lower energy orbit $(E_1)$ is associated with frequency of radiation given as $f = \dfrac{(E_2 - E_1)}{h}$. This condition is Bohr's frequency condition.

In the light of the above statements, choose the correct answer from the options given below:

Revise the formulasAtoms formula sheet: key equations and special cases→