Q 12-12-038JEE MainJEE Main 2024 (1 Feb, Shift 1)Easy
The minimum energy required by a hydrogen atom in the ground state to emit radiation in the Balmer series is nearly
Answer: (D) $12.1\ \text{eV}$
Balmer lines end on $n = 2$, so the atom must first be raised to at least $n = 3$:
$$E = 13.6\left(1 - \frac19\right) = 12.09 \approx 12.1\ \text{eV}$$
Solution by Sreeraj P, M.Sc Physics