Q 12-12-041JEE MainJEE Main 2024 (4 Apr, Shift 2)Easy
According to Bohr's theory, the moment of momentum of an electron revolving in the $4^{\text{th}}$ orbit of a hydrogen atom is
Answer: (D) $2\dfrac{h}{\pi}$
$L = \dfrac{nh}{2\pi} = \dfrac{4h}{2\pi} = 2\dfrac{h}{\pi}$.
Solution by Sreeraj P, M.Sc Physics