Q 12-12-043JEE MainJEE Main 2024 (5 Apr, Shift 2)Easy
The angular momentum of an electron in a hydrogen atom is proportional to (where $r$ is the radius of the orbit of the electron)
Answer: (B) $\sqrt r$
From $\dfrac{mv^2}{r} = \dfrac{ke^2}{r^2}$, $v \propto \dfrac{1}{\sqrt r}$. So $L = mvr \propto \sqrt r$.
Solution by Sreeraj P, M.Sc Physics