Q 12-12-042JEE MainJEE Main 2024 (5 Apr, Shift 1)Easy
An electron rotates in a circle around a nucleus having positive charge $Ze$. The correct relation between the total energy ($E$) of the electron and its potential energy ($U$) is
Answer: (B) $2E = U$
For an electron in a circular orbit, $K = \dfrac{kZe^2}{2r}$ and $U = -\dfrac{kZe^2}{r}$.
$$E = K + U = -\frac{kZe^2}{2r} = \frac{U}{2} \Rightarrow 2E = U$$
Solution by Sreeraj P, M.Sc Physics