Q 11-05-034NEETJEE MainEasy
A force $F = (4 + 6x)$ N acts along the $x$-axis on a body. The work done by it as the body moves from $x = 1$ m to $x = 3$ m is
Answer: (A) $32$ J
$$W = \int_1^3 (4 + 6x)\,dx = \Big[4x + 3x^2\Big]_1^3 = (12 + 27) - (4 + 3) = 32\ \text{J}$$
Solution by Sreeraj P, M.Sc Physics