Q 11-05-039NEETJEE MainMedium
An engine of constant power $60$ kW drives a car of mass $1200$ kg on a level road. The resistance to motion is a constant $2000$ N. The maximum speed of the car is
Answer: (B) $30$ m/s
At maximum speed the acceleration is zero, so the driving force equals the resistance:
$$P = Fv_{max} \;\Rightarrow\; v_{max} = \frac{60000}{2000} = 30\ \text{m/s}$$
Solution by Sreeraj P, M.Sc Physics