Q 11-05-036NEETJEE MainMedium
A $0.5$ kg block moving at $4$ m/s on a smooth floor hits a spring of force constant $200$ N/m. The maximum compression of the spring is
Answer: (C) $0.2$ m
Concept. KE becomes spring PE.
Step 1. Compression. $x = v\sqrt{\dfrac mk} = 4 \times 0.05 = 0.2$ m.
Answer. $0.2$ m (Option C).
Solution by Sreeraj P, M.Sc Physics