Q 11-14-080JEE MainJEE Main 2022 (28 Jul, Shift 1)Easy
In the wave equation $y = 0.5\sin\dfrac{2\pi}{\lambda}(400t - x)$ m the velocity of the wave will be :
Answer: (C) $400\ \text{m s}^{-1}$
Comparing with $y = A\sin\dfrac{2\pi}{\lambda}(vt - x)$, the wave speed is $v = 400\ \text{m s}^{-1}$.
Solution by Sreeraj P, M.Sc Physics