Q 11-14-076JEE MainJEE Main 2022 (26 Jul, Shift 2)Easy
A transverse wave is represented by $y = 2\sin(\omega t - kx)$ cm. The value of wavelength (in cm) for which the wave velocity becomes equal to the maximum particle velocity will be
Answer: (A) $4\pi$
Wave velocity $\dfrac\omega k$ = maximum particle velocity $A\omega$ gives $k = \dfrac1A = \dfrac12\ \text{cm}^{-1}$.
$$\lambda = \frac{2\pi}{k} = 4\pi\ \text{cm}$$
Solution by Sreeraj P, M.Sc Physics