Q 11-14-051JEE MainJEE Main 2023 (31 Jan, Shift 2)Easy
For a solid rod, the Young's modulus of elasticity is $3.2\times10^{11}\ \text{N m}^{-2}$ and density is $8\times10^3\ \text{kg m}^{-3}$. The velocity of longitudinal wave in the rod will be
Answer: (D) $6.32\times10^3\ \text{m s}^{-1}$
$$v=\sqrt{\frac Y\rho}=\sqrt{\frac{3.2\times10^{11}}{8\times10^3}}=\sqrt{4\times10^7}=6.32\times10^3\ \text{m s}^{-1}$$
Solution by Sreeraj P, M.Sc Physics