Q 11-14-008NEETJEE MainEasy
Two points on a progressive wave of wavelength $60$ cm are $10$ cm apart along the direction of propagation. The phase difference between them is
Answer: (D) $\dfrac{\pi}{3}$
$\Delta\phi = \dfrac{2\pi}{\lambda}\Delta x = \dfrac{2\pi}{60} \times 10 = \dfrac{\pi}{3}$.
Solution by Sreeraj P, M.Sc Physics