Q 11-14-008NEETJEE MainEasy
Two points on a progressive wave of wavelength $60$ cm are $10$ cm apart along the direction of propagation. The phase difference between them is
Answer: (D) $\dfrac{\pi}{3}$
Concept. Phase difference $\Delta\phi = \dfrac{2\pi}{\lambda}\Delta x$.
Step 1. Substitute.
$$\Delta\phi = \frac{2\pi}{60} \times 10 = \frac{\pi}{3}$$
Answer. $\dfrac{\pi}{3}$ (Option D).
Solution by Sreeraj P, M.Sc Physics