Q 11-14-011NEETJEE MainMedium
A uniform rope of mass $m$ and length $L$ hangs from a ceiling. The speed of a transverse pulse at a distance $x$ from its lower end is
Answer: (C) $\sqrt{gx}$
The tension at height $x$ supports the rope below: $T = \dfrac{m}{L}xg$. With $\mu = \dfrac{m}{L}$: $v = \sqrt{\dfrac{T}{\mu}} = \sqrt{gx}$.
Solution by Sreeraj P, M.Sc Physics