Q 12-10-159JEE MainJEE Main 2025 (3 Apr, Shift 1)Easy
Two coherent monochromatic light beams of intensities $4I$ and $9I$ are superimposed. The difference between the maximum and minimum intensities in the resulting interference pattern is $xI$. The value of $x$ is ______.
Numerical value type. Enter your answer.
Answer: 24
$$I_{\max} = \left(\sqrt{4I} + \sqrt{9I}\right)^2 = (2 + 3)^2I = 25I$$
$$I_{\min} = \left(\sqrt{9I} - \sqrt{4I}\right)^2 = (3 - 2)^2I = I$$
$$I_{\max} - I_{\min} = 24I \Rightarrow x = 24$$
Solution by Sreeraj P, M.Sc Physics