Q 12-10-161JEE MainJEE Main 2025 (3 Apr, Shift 2)Easy
Two monochromatic light beams have intensities in the ratio $1 : 9$. An interference pattern is obtained by these beams. The ratio of the intensities of maximum to minimum is:
Answer: (D) $4 : 1$
Amplitudes are in the ratio $\sqrt1 : \sqrt9 = 1 : 3$.
$$\frac{I_{\max}}{I_{\min}} = \frac{(1 + 3)^2}{(3 - 1)^2} = \frac{16}{4} = 4$$
Solution by Sreeraj P, M.Sc Physics