Q 12-10-084JEE MainJEE Main 2023 (13 Apr, Shift 2)Easy
In a Young's double slit experiment, the ratio of amplitude of light coming from slits is $2:1$. The ratio of the maximum to minimum intensity in the interference pattern is
Answer: (D) $9:1$
$$\frac{I_{max}}{I_{min}}=\left(\frac{a_1+a_2}{a_1-a_2}\right)^2=\left(\frac31\right)^2=9:1$$
Solution by Sreeraj P, M.Sc Physics