Q 12-10-083JEE MainJEE Main 2023 (25 Jan, Shift 1)Easy
In Young's double slits experiment, the position of $5^\text{th}$ bright fringe from the central maximum is $5\ \text{cm}$. The distance between slits and screen is $1\ \text{m}$ and wavelength of used monochromatic light is $600\ \text{nm}$. The separation between the slits is
Answer: (A) $60\ \mu\text{m}$
$y_5=\dfrac{5\lambda D}{d}\Rightarrow d=\dfrac{5\times600\times10^{-9}\times1}{0.05}=6\times10^{-5}\ \text{m}=60\ \mu\text{m}$.
Solution by Sreeraj P, M.Sc Physics