Q 12-10-085JEE MainJEE Main 2023 (15 Apr, Shift 1)Easy
A single slit of width $a$ is illuminated by a monochromatic light of wavelength $600\ \text{nm}$. The value of $a$ for which first minimum appears at $\theta=30^\circ$ on the screen will be
Answer: (A) $1.2\ \mu\text{m}$
First minimum: $a\sin\theta=\lambda\Rightarrow a=\dfrac{600\ \text{nm}}{0.5}=1.2\ \mu\text{m}$.
Solution by Sreeraj P, M.Sc Physics