Q 11-01-217JEE MainJEE Main 2019 (10 Apr, Shift 2)Easy
In the formula $X = 5YZ^2$, $X$ and $Z$ have dimensions of capacitance and magnetic field, respectively. What are the dimensions of $Y$ in SI units?
Answer: (D) $[M^{-3}L^{-2}T^8A^4]$
$[C] = M^{-1}L^{-2}T^4A^2$ and $[B] = MT^{-2}A^{-1}$, so $[B^2] = M^2T^{-4}A^{-2}$.
$$[Y] = \frac{[X]}{[Z^2]} = \frac{M^{-1}L^{-2}T^4A^2}{M^2T^{-4}A^{-2}} = M^{-3}L^{-2}T^8A^4$$
Solution by Sreeraj P, M.Sc Physics