Q 11-11-138JEE MainJEE Main 2020 (7 Jan, Shift 1)Easy
A Carnot engine operates between two reservoirs of temperatures $900$ K and $300$ K. The engine performs $1200$ J of work per cycle. The heat energy (in J) delivered by the engine to the low temperature reservoir, in a cycle, is ______.
Numerical value type. Enter your answer.
Answer: 600
$\eta = 1 - \dfrac{300}{900} = \dfrac23$.
Heat taken in: $Q_1 = \dfrac{W}{\eta} = \dfrac{1200}{2/3} = 1800$ J.
Heat rejected: $Q_2 = Q_1 - W = 1800 - 1200 = 600$ J.
Solution by Sreeraj P, M.Sc Physics